Aanchal K.

asked • 07/02/17# eliminate theta from the relation a sec theta=1-b tan theta and a square sec square theta=5+b square tan square theta

pls answer to this question urgent...

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## 1 Expert Answer

Ira S. answered • 07/02/17

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I think your equations are

asecΘ = 1-btanΘ

a

^{2}sec^{2}Θ = 5+b^{2}tan^{2}Θ^{}You can use the identity tan

^{2 }Θ + 1 = sec^{2}Θ and you can replace in the second equation^{}it becomes a

^{2}(tan^{2 }Θ+1) = 5 + b^{2}tan^{2}Θa

^{2}tan^{2}Θ - b^{2}tan^{2 }Θ = 5 - a^2^{}tan

^{2}Θ ( a^{2}-b^{2}) = 5-a^{2}tan Θ = (5-a

^{2})/(a^{2}-b^{2})Θ = tan

^{-1}[ (5-a^{2})/(a^{2}- b^{2})You can now substitute this into the first equation

Hope this helped

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Kenneth S.

^{2}] and, for theta, the symbol found in the pulldown menu when you click on the capital OMEGA symbol (which is just to the right of the squaring key.^{2}is pronounced, and written, as "x squared."07/02/17